Using Regular Expression in Ax 2009

Hi Guys,
Here i posted a small job , to explain how we use regular expressin in Axapta. Try it.
static void RegularExpression_Test()
int nameLength,myStringLength;
str myname = “Vasanth”;
str myString = “1234″;
str formatString , formatString1;
System.Text.RegularExpressions.Regex regEx;
System.Text.RegularExpressions.Regex regEx1;
System.Text.RegularExpressions.Match regMatch;
InteropPermission permission = new InteropPermission(InteropKind::ClrInterop);
boolean retVal, retVal1;
nameLength = strLen(myname);
myStringLength = strLen(myString);
formatString   = strfmt(@”^[0-9]{%1}”, myStringLength);
formatString1   = strfmt(@”^[a-zA-Z ]{%1}”, nameLength);
//BP Deviation documented
regEx = new System.Text.RegularExpression.Regex(formatString);
regEx1 = new System.Text.RegularExpression.Regex(formatString1);
regMatch = regEx.Match(myString);
retVal = regMatch.get_Success();
print retVal; // Returns True;
regMatch = regEx1.Match(myname);
retVal1 = regMatch.get_Success();
print retVal1 // Returns True;

Thanks & Regards,
Vasanth Arivali

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